(2x^1/5y^3)(1/3x^-2/3y^2/9)

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Solution for (2x^1/5y^3)(1/3x^-2/3y^2/9) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

((2*x^1)/5)*y^3*(((((1/3)*x^-2)/3)*y^2)/9) = 0

((2*x)/5)*y^3*(((((1/3)*x^-2)/3)*y^2)/9) = 0

2/405*x^-1*y^5 = 0 // : 2/405*y^5

x^-1 = 0

x należy do O

x belongs to the empty set

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